[M.27L]                                                               [M.27]
The management of the vault in the tomb of Can Signorio is            No 6.	Verona.  Scala Monuments.	27
strange [diagram] it is flat domical; perfectly flat                  
done at the top, with a circle                                        		Fig 3.  Section of mouldings as they fall on the hexagonal
in the centre, rudely cut, with a                                     		abacus head of one of the six main twisted shafts of the
lamb and flag: a b is the                                             		upper story of the tomb of Can Signorio.  Its measures
vaulting rib at the top: from the ceiling:  but only d e at the       		are; a b, 6 in;  b c, (the intermediate points inaccessible)
bottom:  the additional member c stealing out as it rises. Probably   		3 in;  c-d, 4:  notethat the line did not bend in
this is owing to the plaster filling.                                 		coming tight from c to d:  so the line d d2 must be wrong
                                                                      		d-e is right, at rt angles to the line the rough middle of
                                                                      		hexagon:  it is the foliation moulding (i e d3-h2) and it
                                                                      		is curious that it falls altogether outside of the point n.
                                                                      		of the hexagon:  so that the line n n2, would entirely miss it.
                                                                      		c c2 is the flower moulding following the large arch:  I think
                                                                      		the part at c looks clumsy & projects too much:  (I see my
                                                                      		error now:  I have drawn the series of lines parallel with
                                                                      		d d2, as if they were parallel with the side of hexagon:
                                                                      		whereas they ought to be at the hexagon angle on the line
                                                                      		h2 i, and ought to point to n3 as h2 i points to m:
                                                                      		which it did exactly) with this alteration, and taking the
                                                                      		following and preceding measures, it will be right.  d-e 1¼ in;  e-h ¾.
                                                                      		h2 i, 4¼ i-k ½ or ¾:  k-l (round) 4½ l-m, ¾ or 1.
                                                                      		finally n to the level h2 i, in direction n n2 marked by dotted
                                                                      		line, 3¾.  From n to the opposite corresponding point
                                                                      		of the next shaft is 3 ft 8:  the enclosing arch springing from
                                                                      		the point h2, we have to add 3¾ at each side, giving 4 ft 3½  for 

[Version 0.05: May 2008]