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                                                                      		   No 6.	   VERONA   SCALA  MONUMENTS.
The management of the vault in the tomb of Car Syonois is strange     	Fig 3.  Section of mouldings as they fall on the hexagonal
		it is flat domical, perfectly flat done at                          abacus head of one of the six main twisted shafts of the
				the top with a circle in the centre                               upper story of the tomb of Can Signoris.  Its measures are
		           rudely cut, with a lamb[g] and flag                      a, b, 6 in;  b, c, (the intermediate points inaccessible)
			a b is the vaulting rib at the top:                                3 in;  c-d, 4:  notethat the line did not bend in coming
	from the ceiling:  but only d e at the bottom:  the additional       tight from c to d:  so the line d d2 must be wrong
	member c stealing out as it rises  - probably this is owing to       d-e is right, at rt angles to the line the rough middle of
	the plaster falling.                                                 hexagon:  it is the foliation moulding (i e d3-h2) and it
                                                                      is curious that it falls altogether outside of the
                                                                      point n. of the hexagon:  so that the line n n2, would
                                                                      entirely miss it, c c2 is the flower moulding following
                                                                      the large arch:  I think the pas[r]t at c looks clumsy and
                                                                      forgets too much:  (I see my error now:  I have drawn the
                                                                      series of lines parallel with d d2, as if they were
                                                                      parallel with the side of hexagon:  whereas they ought to
                                                                      be at the hexagon angle on the line h2i, and ought to
                                                                      point to n3 as h2i points to m:  which it did exactly)
                                                                      with this alteration, and taking this following and
                                                                      preceeding meanness, it will be right.  d-e 1¼in;  e-h ¼
                                                                      h2i, 4¼ i-k ½ or ¾:  k-l (round) 4½ 2 m, ¼ or 1 finally
                                                                      n to the level h2i, in direction or n2 marked by dotted
                                                                      line, 3¾.  From n to the opposite corresponding point
                                                                      of the next shaft si 3 ft 8:  the enclosing arch springing
                                                                      from the point h2, we have to add 3¾ at each side, giving
                                                                      4 ft 3½  for 

[Version 0.05: May 2008]